Tyt Matematik Orijinal Soru Bankası May 2026

Many "original" problems have 2 valid answers but only one fits real-world logic (e.g., age can’t be negative, number of students can’t be fractional). 4. Sample Original-Style Question (Free for your content) Problem: A teacher writes a two-digit number on the board. She says: "If you add 45 to this number, you get the reverse of its digits. Also, the product of the digits is 1 less than half of the original number." Find the number. Solution walkthrough (for your subscribers): Let digits = 10a + b. (1) 10a + b + 45 = 10b + a → 9a – 9b = –45 → a – b = –5 → b = a + 5. (2) a * b = (10a + b)/2 – 1 → Multiply: 2ab = 10a + b – 2. Substitute b = a+5: 2a(a+5) = 10a + a+5 – 2 → 2a²+10a = 11a + 3 → 2a² – a – 3 = 0 → (2a–3)(a+1)=0 → a=1.5 or a=–1. So a=1.5? Impossible. Contradiction? Wait – the wording says half of the original number – but original number might be odd → half is not integer. That’s the original twist : The product being "1 less than half" forces us to check integer domains.

Orijinal questions often hide clear notation. Rewrite the situation as an equation before solving. tyt matematik orijinal soru bankası

(Actually solve correctly: b = a+5, a ≤4, so a=1, b=6; a=2,b=7; a=3,b=8; a=4,b=9. Check eq (2): 2ab = 10a+b–2. Try a=3,b=8: 2 24=48, right side 30+8–2=36 → no. a=4,b=9: 2 36=72, right 40+9–2=47 → no. So no integer solution? The twist: They said "product of digits is 1 less than half of the original" – maybe original is 10b+a? Test reversed: Let original=10b+a. Then adding 45: 10b+a+45=10a+b → 9b–9a=–45 → b–a=–5 → a=b+5, impossible. So the real answer: 16? Check 16+45=61 (reverse yes). Product=6, half of 16=8, 1 less than 8 is 7, not 6. So no solution? That’s the trap – Orijinal banks include unsolvable problems to teach variable checking. Correct answer: No such number exists → teaches critical thinking before calculation.) Many "original" problems have 2 valid answers but