Answer: Each bulb current ( I = P/V = 10/220 = 1/22 , \text{A} ) Number = total current / bulb current = ( 5 / (1/22) = 110 ) bulbs
Answer: (i) 9 Ω = two in parallel (3 Ω) + one in series (6 Ω) (ii) 4 Ω = two in series (12 Ω) in parallel with one (6 Ω): ( 1/R = 1/12 + 1/6 = 3/12 ) → R=4 Ω class 10 electricity ncert solutions
Answer: The SI unit of electric current is ampere (A) . 1 ampere = 1 coulomb per second (1 A = 1 C/s). Answer: Each bulb current ( I = P/V